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Question

Bonjour,


J'ai des équations à résoudre :


c. 4+3x/5 = 7x-1/8
d. 6-x/3 = 4x+1/2

1 Réponse

  • Réponse :

    bonjour,

    (4+3x)/5 = (7x-1)/8

    (4+3x)/5  - ( 7x - 1)/8 = 0

    8(4+3x)/5×8 - 5(7x - 1)/8×5  = 0

    (32 +24x) / 40 - (35x - 5)/40 = 0

    (32 + 24x-35x + 5)/40 = 0

    (-11x+37)/40 = 0

    -11x + 37 = 0

    -11x = -37

    x = -37/-11

    x = 37/11

    (6-x)/3 = (4x+1)/2

    (6-x)/3 - (4x+1)/2 = 0

    2 (6-x) / 3×2 - 3(4x+1)/2×3 = 0

    (12 - 2x)/6 - (12x +3)/6 = 0

    (12 -2x -12x-3)/6 = 0

    (-14x + 9 ) / 6 = 0

    -14x + 9 = 0

    -14x = -9

    x = -9/-14

    x = 9/14

    voila :)

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