EXERCICES MATH AIDEZ MOI SVP Factoriser les expressions suivantes comme dans l'exemple : z = 5(x + 1) + 3(x+1) A = 13(x + 2) + 5(x + 2) B = 7(2x - 3) + 2(2x - 3

bonjour

z = 5(x + 1) + 3(x+1)

z = ( x + 1 ) ( 5 + 3 ) = 8 ( x + 1 )

A = 13(x + 2) + 5(x + 2)

A =  ( x + 2 ) ( 13 + 5 ) = 18 ( x + 2 )

B = 7(2x - 3) + 2(2x - 3)

B = ( 2 x - 3 ) ( 7 + 2 ) = 9 ( 2 x - 3 )

Z = (x + 1)(5+3)  est déjà factorisé

Z = 8(x + 1)  déjà factorisé

C = 3x(x + 2) -5(x + 2)

C = ( x + 2 ) ( 3 x - 5 )

D = 4(x + 3) + 9x(x + 3)

D = ( x + 3 ) ( 4 + 9 x )

E = 7x(3x + 1) - 10x(3x + 1)

E = ( 3 x + 1 ) ( 7 x - 10 x =  - 3 x ( 3 x + 1 )  

Réponse:

z = 5(x + 1) + 3(x+1) = (5+3) ( x+1)= 8(x+1)

A = 13(x + 2) + 5(x + 2)= (13+5)(x+2)= 18(x+2)

B = 7(2x - 3) + 2(2x - 3)=(7+2)(2x-3)=9(2x-3)

Z = (x + 1)(5+3)= 8(x + 1)

C = 3x(x + 2) -5(x + 2) = (3x-5)(x+2)

D = 4(x + 3) + 9x(x + 3)= (4+9x)(x+3)

E = 7x(3x + 1) - 10x(3x + 1) =(7x-10x)(3x+1)= -3x(3x+1)